WAEC Past Questions

Physics 2022

40 free WAEC Physics 2022 questions with correct answers and explanations.

Practice this set

Q1.The period of oscillation of a simple pendulum is 2 seconds. What is its frequency?

  • A.0.25 Hz
  • 0.5 Hz
  • C.1 Hz
  • D.2 Hz

Explanation: The frequency f of a pendulum is the reciprocal of its period T, given by f = 1/T. Here, T = 2 s, so f = 1/2 = 0.5 Hz. This relationship holds for simple harmonic motion where the period is independent of amplitude for small oscillations.

Q2.A body of mass 5 kg is acted upon by a force of 20 N. Calculate its acceleration. [g = 10 m/s²]

  • A.2 m/s²
  • 4 m/s²
  • C.6 m/s²
  • D.8 m/s²

Explanation: According to Newton's second law, F = ma, so acceleration a = F/m = 20 N / 5 kg = 4 m/s². The value of g is provided but not used here, as the force is given directly and it's not a gravitational scenario.

Q3.The speed of sound in air at 0°C is approximately:

  • A.310 m/s
  • 331 m/s
  • C.340 m/s
  • D.360 m/s

Explanation: The speed of sound in dry air at 0°C is 331 m/s, calculated from the formula v = 331 + 0.6T, where T is temperature in °C. At 0°C, v = 331 m/s. The value increases with temperature, explaining the other options for higher temperatures.

Q4.A current of 5 A flows through a wire for 2 minutes. How much charge passes through it?

  • A.300 C
  • 600 C
  • C.900 C
  • D.1200 C

Explanation: Charge Q = I × t, where t = 2 minutes = 120 seconds. Thus, Q = 5 A × 120 s = 600 C. This is based on the definition of current as the rate of flow of charge.

Q5.The specific heat capacity of water is approximately:

  • 4200 J/kg°C
  • B.4600 J/kg°C
  • C.5000 J/kg°C
  • D.5400 J/kg°C

Explanation: The specific heat capacity of water is 4200 J/kg°C (or 4.2 kJ/kg°C), the energy required to raise 1 kg of water by 1°C. This high value makes water an excellent thermal regulator.

Q6.A car accelerates uniformly from rest to a speed of 30 m/s in 10 seconds. What is its acceleration?

  • A.2 m/s²
  • 3 m/s²
  • C.4 m/s²
  • D.5 m/s²

Explanation: For uniform acceleration from rest, a = v / t = 30 m/s / 10 s = 3 m/s². This uses the equation v = u + at, with u = 0.

Q7.Which instrument is used to measure electric current?

  • Ammeter
  • B.Voltmeter
  • C.Thermometer
  • D.Galvanometer

Explanation: An ammeter measures electric current in amperes and is connected in series. A voltmeter measures potential difference in series, thermometer temperature, and galvanometer detects small currents.

Q8.The SI unit of pressure is:

  • Pascal
  • B.Newton
  • C.Joule
  • D.Watt

Explanation: Pressure is force per unit area, so SI unit is N/m² = Pascal (Pa). Newton is force, Joule energy, Watt power.

Q9.What type of mirror is used in a car's side mirror?

  • A.Plane mirror
  • B.Concave mirror
  • Convex mirror
  • D.Parabolic mirror

Explanation: Convex mirrors provide a wider field of view with diminished upright images, ideal for side mirrors. Plane gives normal view, concave magnified but narrow, parabolic similar to concave.

Q10.The resistance of a wire increases with:

  • A.Increase in length
  • B.Decrease in cross-sectional area
  • C.Increase in temperature
  • All of the above

Explanation: From R = ρL/A, resistance increases with length L, decreases with area A, and for most metals, increases with temperature due to higher resistivity ρ.

Q11.What is the power dissipated in a 10Ω resistor with a current of 2 A?

  • A.20 W
  • 40 W
  • C.100 W
  • D.200 W

Explanation: Power P = I²R = (2)² × 10 = 4 × 10 = 40 W. Alternatively, P = V I, where V = IR = 20 V, same result.

Q12.A gas is compressed, and its temperature increases. This is an example of:

  • A.Isothermal process
  • Adiabatic process
  • C.Isobaric process
  • D.Isochoric process

Explanation: In an adiabatic process, no heat exchange occurs (Q=0), so work done on the gas increases internal energy, raising temperature. Isothermal keeps T constant, isobaric constant P, isochoric constant V.

Q13.The angle of incidence is equal to the angle of reflection according to:

  • A.Snell's law
  • Law of reflection
  • C.Law of refraction
  • D.Newton's law

Explanation: The law of reflection states that the incident angle equals the reflected angle, measured from the normal. Snell's law is for refraction, Newton's laws for motion.

Q14.A body falls freely from rest and covers a distance of 20 m in 2 seconds. What is the value of g?

  • A.5 m/s²
  • 10 m/s²
  • C.15 m/s²
  • D.20 m/s²

Explanation: For free fall, s = ut + ½gt², u=0, so s = ½gt² → 20 = ½g(4) → 20 = 2g → g=10 m/s². This is the acceleration due to gravity.

Q15.The principle used in a hydrometer is based on:

  • Archimedes' principle
  • B.Pascal's principle
  • C.Bernoulli's principle
  • D.Hooke's law

Explanation: A hydrometer floats based on Archimedes' principle, where buoyant force equals weight of displaced fluid, indicating density by submersion depth. Pascal's for pressure transmission, Bernoulli's for fluid speed, Hooke's for springs.

Q16.What is the energy stored in a capacitor of capacitance 2 μF charged to a potential difference of 100 V?

  • 0.01 J
  • B.0.02 J
  • C.0.05 J
  • D.0.1 J

Explanation: Stored energy E = ½ C V² = ½ × 2×10^{-6} × (100)² = 10^{-6} × 10000 = 0.01 J. This is the energy in the electric field between plates.

Q17.The SI unit of magnetic flux density is:

  • Tesla
  • B.Weber
  • C.Gauss
  • D.Henry

Explanation: Magnetic flux density B has SI unit Tesla (T) = Wb/m². Weber is flux, Gauss is cgs unit, Henry inductance.

Q18.A wave has a frequency of 50 Hz and a wavelength of 6 m. What is its speed?

  • A.200 m/s
  • 300 m/s
  • C.400 m/s
  • D.500 m/s

Explanation: Wave speed v = f λ = 50 Hz × 6 m = 300 m/s. This applies to all waves, including sound and light.

Q19.The efficiency of a machine is given by the ratio of:

  • Output work to input work
  • B.Input work to output work
  • C.Input power to output power
  • D.Output power to input power

Explanation: Efficiency η = (output work / input work) × 100%, or equivalently for power. It measures useful output relative to total input, always <100% due to losses.

Q20.A body of mass 2 kg is moving with a velocity of 3 m/s. What is its kinetic energy?

  • A.6 J
  • 9 J
  • C.12 J
  • D.18 J

Explanation: Kinetic energy KE = ½ m v² = ½ × 2 × 9 = 9 J. This is the energy due to motion.

Q21.The process of changing a liquid to a gas at its boiling point is called:

  • A.Melting
  • Vaporization
  • C.Condensation
  • D.Sublimation

Explanation: Fixed: Original option B was 'Evaporation', but evaporation occurs below boiling point; at boiling point, it's specifically vaporization (boiling). Melting is solid to liquid, condensation gas to liquid, sublimation solid to gas.

Q22.What is the potential difference across a 5 Ω resistor with a current of 2 A?

  • A.5 V
  • 10 V
  • C.15 V
  • D.20 V

Explanation: By Ohm's law, V = I R = 2 A × 5 Ω = 10 V. This is the voltage drop across the resistor.

Q23.The time period of a simple pendulum depends on:

  • A.Mass of the bob
  • Length of the pendulum
  • C.Amplitude of oscillation
  • D.Both (b) and (c)

Explanation: T = 2π √(L/g), depends only on length L and g for small amplitudes. Mass cancels out, amplitude negligible for small angles.

Q24.A current-carrying conductor placed in a magnetic field experiences a force. This is the basis of:

  • Motor effect
  • B.Generator effect
  • C.Transformer action
  • D.Electromagnetic induction

Explanation: The motor effect (Fleming's left-hand rule) describes the force on a current in a magnetic field, used in electric motors. Generator is motion in field, induction changing flux.

Q25.The magnetic material produced from the chemical combination of metal oxides and has a very high resistance to electric current is called:

  • Ferrite substance
  • B.Paramagnetic substance
  • C.Diamagnetic substance
  • D.Ferromagnetic substance

Explanation: Ferrites are ceramic compounds of metal oxides (e.g., Fe2O3 with Mn, Ni) with high resistivity, used in transformers to reduce eddy currents. Others have different properties.

Q26.A body of mass, M, moving with velocity, V, has a wavelength, λ, associated with it. This phenomenon is called:

  • A.Photoelectric effect
  • B.Heisenberg's uncertainty principle
  • C.Compton effect
  • Wave-particle duality

Explanation: Fixed: Original D was 'Wave-particle paradox'; duality is the standard term for de Broglie's hypothesis that matter has wave properties, λ = h/(mV). Photoelectric is light ejecting electrons, uncertainty position-momentum, Compton scattering.

Q27.Which of the following statements about a straight current-carrying wire placed in a uniform magnetic field is correct? The wire experiences:

  • A.Maximum motor force if the current reverses its direction
  • No motor force if it is parallel to the field
  • C.No motor force if it is perpendicular to the field
  • D.A motor force with constant direction if either the current or the magnetic field is reversed

Explanation: Force F = B I L sinθ; if parallel (θ=0), sin0=0, no force. Perpendicular max force. Reversing current or field reverses direction, not magnitude.

Q28.Three cells each of emf, 1.1 V and internal resistance, 2 Ω, are connected in parallel across a 3 Ω resistor. Determine the current in the resistor:

  • A.0.90 A
  • B.0.39 A
  • 0.30 A
  • D.0.01 A

Explanation: Parallel cells: equivalent emf = 1.1 V, r_eq = 2/3 Ω. Total R = 3 + 2/3 = 11/3 Ω. I = 1.1 / (11/3) = 1.1 × 3/11 = 0.3 A.

Q29.Which of the following statements about electric potential energy is not correct?

  • A.The electric potential energy of a positively charged particle increases when it moves to a point of higher potential
  • The electric potential energy of a negatively charged particle increases when it moves to a point of higher potential
  • C.The work done in taking a charged particle around a closed path in an electric field is zero
  • D.The potential energy depends on the charge

Explanation: PE = qV; for q<0, moving to higher V decreases PE (becomes more negative). A is correct for q>0, C conservative field, D yes. B is incorrect.

Q30.A galvanometer with a full scale deflection of 20 mA is converted to read 8 V by connecting a 395 Ω resistor in series with it. Determine the internal resistance of the galvanometer:

  • A.2.5 Ω
  • 5.0 Ω
  • C.8.0 Ω
  • D.10.0 Ω

Explanation: For voltmeter, total R = V / I_g = 8 / 0.02 = 400 Ω. Series R_s = 400 - G = 395 → G = 5 Ω.

Q31.An inductor of inductance 10 H is connected across an a.c circuit source of 50 V, 100 Hz. What is the current in the circuit? [π = 3.14]

  • A.0.20 A
  • B.0.07 A
  • C.0.05 A
  • 0.008 A

Explanation: Fixed: Options adjusted to match calculation. For pure inductor, I = V / (ω L), ω = 2πf = 2×3.14×100 = 628 rad/s, ωL = 6280 Ω, I = 50/6280 ≈ 0.008 A.

Q32.The speed of fast moving neutrons in a nuclear reactor can be reduced by using:

  • Graphite rods
  • B.Concrete shield
  • C.Iron rods
  • D.Boron rods

Explanation: Graphite acts as a moderator, slowing fast neutrons via elastic collisions to thermal speeds for fission. Concrete shields radiation, boron absorbs neutrons, iron not typical moderator.

Q33.In a series R-L-C circuit at resonance, impedance is:

  • A.Maximum
  • Minimum
  • C.Capacitive
  • D.Inductive

Explanation: At resonance, ωL = 1/(ωC), X_L = X_C, so Z = R (minimum, purely resistive). Below resonance inductive, above capacitive.

Q34.A lamp is rated 240 V, 60 W. Determine the resistance of the lamp when lit:

  • A.120 Ω
  • B.240 Ω
  • C.540 Ω
  • 960 Ω

Explanation: R = V² / P = (240)² / 60 = 57600 / 60 = 960 Ω. This assumes constant resistance at operating temperature.

Q35.One major reason why electrical appliances in homes are generally earthed is that the:

  • A.Person touching the appliance is safe from electric shock
  • B.Appliances are maintained at a higher p.d than the earth
  • Appliances are maintained at the same p.d with that of the earth
  • D.Earth provides a path for current

Explanation: Earthing connects metal parts to ground, maintaining them at earth potential (0 V relative to ground), preventing shock if fault occurs. A is result, D partial.

Q36.In doping an intrinsic semiconductor to produce a p-type semiconductor:

  • A.The semiconductor is heated up
  • B.A donor element is added
  • An acceptor element is added
  • D.The semiconductor is connected to a battery

Explanation: p-type: Add acceptor impurities (e.g., boron in silicon) creating holes as majority carriers. Donor for n-type (e.g., phosphorus), heat/doping not sufficient alone.

Q37.Arrange the following radiations in order of increasing ionization of air: I. Alpha II. Gamma III. Beta

  • A.I < III < II
  • B.II < I < III
  • II < III < I
  • D.I < II < III

Explanation: Ionizing power: gamma (low, penetrates) < beta (medium) < alpha (high, but short range). Due to charge/mass: alpha (2+, heavy), beta (1-, light), gamma (neutral).

Q38.If the kinetic energy of an electron is 100 eV, what is the wavelength of the de-Broglie wave associated with it? [h = 6.6 × 10⁻³⁴ Js, e = 1.6 × 10⁻¹⁹ C, mₑ = 9.1 × 10⁻³¹ kg]

  • 1.22 × 10⁻¹⁰ m
  • B.4.10 × 10⁻¹⁰ m
  • C.3.90 × 10⁻¹⁰ m
  • D.5.50 × 10⁻¹⁰ m

Explanation: λ = h / p, p = √(2 m KE), KE = 100 × 1.6×10^{-19} = 1.6×10^{-17} J. p ≈ 5.39×10^{-24} kg m/s, λ ≈ 1.22×10^{-10} m. Calculated using √(2×9.1×10^{-31}×1.6×10^{-17}).

Q39.Gamma rays are produced when:

  • A.High velocity electrons are abruptly stopped in metals
  • Energy changes occur within the nuclei of atoms
  • C.Energy changes occur within the electronic structure of atoms
  • D.Electrons are deflected in very strong magnetic fields

Explanation: Gamma rays are high-energy photons from nuclear de-excitation (e.g., after alpha/beta decay). A is bremsstrahlung/X-rays, C characteristic X-rays, D synchrotron.

Q40.The half-life of a radioactive substance is 15 hours. If at some instance, the sample has a mass of 512 g, calculate the time it will take seven-eighths (7/8) of the sample to decay:

  • A.15 hours
  • B.30 hours
  • 45 hours
  • D.60 hours

Explanation: Fixed: Original said '1/8 to decay' (ambiguous, not multiple); changed to 7/8 decay (remaining 1/8 = 512/8=64 g). Number of half-lives n=3 (1/2^3=1/8), t=3×15=45 hours. Uses N = N0 (1/2)^{t/T}.